Chemistry

Miscellaneous Everyday Substances Questions

Chapter: Everyday Materials and Their Chemistry | Total Available: 17 Real Questions

Question 1 of 10 Authentic UPSC NDA Question

 Refining of petroleum is carried out usingwhich one of the following techniques?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option (b) is correct. Fractional distillation effectively separates crude petroleum into its components based on boiling points.

πŸ“– Governing Law / Core Concept

The refining of petroleum is governed by the principle of fractional distillation, which relies on the different boiling points of hydrocarbons.

πŸ§ͺ Step-by-Step Breakdown

Crude oil is a complex mixture of hydrocarbons. Through fractional distillation, these hydrocarbons are separated in a distillation column, where:

\[ \text{Fractional Distillation} \] \

The distillation process correlates with the boiling points of the compounds:

Common ranges include:
  • Petrol: 40 - 100 Β°C
  • Kerosene: 150 - 250 Β°C
  • Diesel: 250 - 350 Β°C
  • LPG: below 40 Β°C

πŸ” Option Analysis

  • A: Evaporation - Not suitable as it does not separate based on boiling point.
  • C: Separating funnel - Used for separating immiscible liquids, not applicable here.
  • D: Sublimation - A process for solids that change directly to gas; irrelevant for crude oil.

⚑ Mnemonic / Speed-Run

Remember: "F" for Fractional distillation is for Fluid separation of hydrocarbons by Flowing boiling points.

6. Visual Suggestion

6. Visual Suggestion

A flowchart illustrating the fractional distillation process, including input of crude oil, separation into different fractions at various boiling points, and collection of desired products.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter 5 (States of Matter) and Chapter 12 (Organic Chemistry).

Question 2 of 10 Authentic UPSC NDA Question

Which one of the following is used as a binder in paints ?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option D is correct. Silicones are commonly used as binders in paints due to their excellent adhesion and flexible properties.

πŸ“– Governing Law / Core Concept

In paint formulations, binders are crucial as they provide adhesion, durability, and finish to the paint film. Silicones, particularly in the form of polysiloxanes, are known for their unique properties, which include resistance to temperature extremes and moisture.

πŸ§ͺ Step-by-Step Breakdown

  • Silicone Binders: Composed of silicon-oxygen frameworks, these materials provide superior elasticity and thermal stability.
  • Adhesion: Silicone binders enhance the adhesion of paint to various surfaces, ensuring a long-lasting finish.
  • Flexibility: Their flexibility allows paints to withstand cracking and peeling.

πŸ” Option Analysis

  • A: Titanium dioxide - Primarily a white pigment, not a binder.
  • B: Novolac - A phenolic resin used in specific coatings but not in general paints.
  • C: Phthalocyanine - A pigment known for color, not as a binder.

⚑ Mnemonic / Speed-Run

Remember: "Silicones Stick!" to recall that silicones are effective binders, enhancing adhesion and resilience in paints.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against standard chemistry materials covering polymer science and paint technology.

Question 3 of 10 Authentic UPSC NDA Question

Which one of the following is an example of a clean fuel ?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option [b] is correct. Propane is a clean fuel with lower emissions compared to other options.

πŸ“– Governing Law / Core Concept

Clean fuels are characterized by lower carbon emissions and pollutants during combustion, contributing to a reduction in environmental and health impacts.

πŸ§ͺ Step-by-Step Breakdown

  • Coke: A carbon-rich fuel produced from coal, resulting in high CO2 emissions.
  • Propane: A hydrocarbon (C3H8) with clean-burning properties, emitting only CO2 and water vapor.
  • Petrol: Produces CO2, NOx, and particulate matter, making it less clean than propane.
  • Wax: While it burns cleanly, it isn’t typically classified as a fuel for combustion engines or heating.

πŸ” Option Analysis

A: Coke contributes significantly to air pollution.
B: Propane is indeed a clean fuel option.
C: Petrol has substantial pollutants compared to propane.
D: Wax is not commonly used as a fuel source.

⚑ Mnemonic / Speed-Run

Remember: Propane = Cleanest fuel. (Propane emits the fewest pollutants.)

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against environmental science principles regarding clean fuels and emissions.

Question 4 of 10 Authentic UPSC NDA Question

Common salt (NaCl) is not used as a raw material for preparation of which one of the following compounds?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option (C) is correct. Common salt (NaCl) is not used in the manufacture of plaster of Paris.

πŸ“– Governing Law / Core Concept

The preparation of plaster of Paris involves gypsum (calcium sulfate dihydrate, \( \text{CaSO}_4 \cdot 2\text{H}_2\text{O} \)), not sodium chloride (NaCl).

πŸ§ͺ Step-by-Step Breakdown

Plaster of Paris is produced by heating gypsum:

\[ \text{CaSO}_4 \cdot 2\text{H}_2\text{O} \xrightarrow{\Delta} \text{CaSO}_4 \cdot \frac{1}{2}\text{H}_2\text{O} + 1.5\text{H}_2\text{O} \]

In comparison:

  • Option A: Bleaching Powder is made from chlorine and slaked lime.
  • \[ \text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{Ca(OCl)}_2 + \text{HCl} \]
  • Option B: Baking Soda is produced from sodium carbonate and carbon dioxide.
  • \[ \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow 2 \text{NaHCO}_3 \]
  • Option D: Washing Soda is made by the reaction of sodium carbonate sesquihydrate with water.
  • \[ \text{Na}_2\text{CO}_3 + 10 \text{H}_2\text{O} \rightarrow \text{Na}_2\text{CO}_3 \cdot 10\text{H}_2\text{O} \]

πŸ” Option Analysis

While NaCl is used in making washing soda, baking soda, and bleaching powder, it is not a component in the synthesis of plaster of Paris, which exclusively requires gypsum.

⚑ Mnemonic / Speed-Run

Remember: "Sodium is for soda, but gypsum is for plaster."

6. Visual Suggestion

6. Visual Suggestion

Diagram showing the thermal decomposition of gypsum to plaster of Paris, with labels for reactants, products, and reaction conditions.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XI Chemistry, Chapter 2 (Structure of Atom and Periodicity in Properties).

Question 5 of 10 Authentic UPSC NDA Question

Solder is an alloy of

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option (c) is correct. Solder is primarily composed of lead (Pb) and tin (Sn).

πŸ“– Governing Law / Core Concept

Soldering involves an alloy of lead and tin, which melts at a lower temperature (around 180-190 Β°C) compared to pure metals, allowing for effective joining without damaging components.

πŸ§ͺ Step-by-Step Breakdown

Solder primarily consists of:

  • Lead (Pb): a soft, malleable metal.
  • Tin (Sn): a metal that provides strength and corrosion resistance.

The typical composition is:

  • 60% Tin (Sn) to 40% Lead (Pb).
  • Other proportions can include up to 90% Sn and 10% Pb.

These alloys make solder suitable for electronic and plumbing applications.

πŸ” Option Analysis

Other options are incorrect because:

  • A: Copper (Cu) and tin (Sn) form bronze, not solder.
  • B: Iron (Fe) and zinc (Zn) create galvanization, not solder.
  • D: Silver (Ag) and zinc (Zn) are not used in soldering.

⚑ Mnemonic / Speed-Run

Remember "Lead and Tin Got Soldered In" to recall that solder is made from lead (Pb) and tin (Sn).

6. Visual Suggestion

6. Visual Suggestion

A table comparing the properties of solder alloys, including melting points and typical applications, would enhance understanding.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter on Alloys and their Applications.

Question 6 of 10 Authentic UPSC NDA Question

Which one of the following is not used raw material in the manufacture of glass

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option D is correct. Gypsum is not a raw material in glass manufacturing.

πŸ“– Governing Law / Core Concept

Glass is primarily made from silicate materials through a melting process involving silica (SiOβ‚‚), soda (Naβ‚‚CO₃), and alumina (Alβ‚‚O₃). Gypsum (CaSOβ‚„Β·2Hβ‚‚O) is mainly used in the production of cement and mortar.

πŸ§ͺ Step-by-Step Breakdown

In the glass manufacturing process, the commonly used raw materials are:

  • Soda (sodium carbonate) helps reduce the melting temperature.
  • Alumina enhances the durability of the glass.
  • Borax (sodium borate) can be used to improve glass clarity and strength.
  • Gypsum is not utilized in this process.

The relevant chemical reaction can be summarized as:

\[ \text{Silica} + \text{Soda} + \text{Alumina} \rightarrow \text{Glass} \]

πŸ” Option Analysis

Gypsum (Option D) is used in constructing cement, while:

  • Soda (Option A): Used for reducing melting point.
  • Alumina (Option B): Improves quality and stability.
  • Borax (Option C): Enhances glass characteristics.

⚑ Mnemonic / Speed-Run

Remember the key raw materials with the mnemonic: "SAB G" (Soda, Alumina, Borax = Glass), contrasting with Gypsum.

6. Visual Suggestion

6. Visual Suggestion

A flowchart illustrating the glass production process, highlighting inputs (Silica, Soda, Alumina) and the resulting glass product, with Gypsum distinctly noted as not included.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter on General Principles and Processes of Isolation of Elements.

Question 7 of 10 Authentic UPSC NDA Question

Which one of the following is commonly used as an ‘anti-skinning agent’ in paints?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option (b) is correct. N-methyl pyrrolidone is a well-known anti-skinning agent.

πŸ“– Governing Law / Core Concept

N-methyl pyrrolidone (NMP) is utilized in coatings and paints to mitigate skin formation during the curing process through its ability to lower surface tension.

πŸ§ͺ Step-by-Step Breakdown

NMP acts by reducing the surface tension of the paint, leading to a more uniform dispersion of components and inhibition of skin formation:

\[ \text{Surface Tension (ST)} \rightarrow \text{Reduced by adding NMP} \]

When added, NMP interacts with both polar and non-polar solvents, promoting a homogeneous mixture:

\[ \text{SKIN FORMATION} \rightarrow \text{Avoided with NMP} \]

πŸ” Option Analysis

  • A: Gelatin - A natural protein; ineffective as an anti-skinning agent.
  • C: Pyridine - A basic organic compound; does not serve to prevent skinning.
  • D: Polyhydroxy phenol - A phenolic compound with applications differing from skin prevention.

⚑ Mnemonic / Speed-Run

Remember "NMP Stops Paint Skin," to directly connect N-methyl pyrrolidone to its anti-skinning effect.

6. Visual Suggestion

6. Visual Suggestion

Consider a flowchart that illustrates the role of NMP in paint formulations, showing the process of skin formation prevention and improvements in the paint's aesthetic and performance characteristics.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XI Chemistry, Chapter on Organic Compounds.

Question 8 of 10 Authentic UPSC NDA Question

Which one of the following metal is NOT an essential component in stainless steel ?

Step-by-Step Logic & Solution

Explanation: Steel does not contain Sn. Steel = Fe = 72%, Cr = 17-19%, Ni = 7-9%, with carbon.

Question 9 of 10 Authentic UPSC NDA Question

For manufacturing of glass, which among the following is used as a source of silica ?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option D is correct. Sand is primarily composed of silica, making it the main source of silicon dioxide in glass manufacture.

πŸ“– Governing Law / Core Concept

The production of glass primarily involves the chemical composition of silica, \( SiO_2 \), which constitutes approximately 95% of glass.

πŸ§ͺ Step-by-Step Breakdown

For manufacturing glass, the following materials are compared:

  • A: Fine clay soil - Composed mainly of alumina (\( Al_2O_3 \)) and silica, but not used because it contains too much alumina.
  • B: Wood powder - Contains organic compounds, not a source of silica.
  • C: Coconut shell - Primarily carbon, not relevant for silica content.
  • D: Sand - Composed mainly of silicon dioxide, making it the key raw material for glass production.

Thus, the chemical reaction for the formation of glass from sand can be simplified as:

\[ SiO_2 \rightarrow Glass\]

πŸ” Option Analysis

The other options are incorrect as they do not serve as viable sources of silica. Clay does contain silica but is not used for glass manufacturing due to its chemical composition. Wood powder and coconut shells are composed of organic materials and do not provide silicon dioxide.

⚑ Mnemonic / Speed-Run

Remember: Sand for Silica - The 3 S's rule: Silica, Sand, and Synthesis for glass.

6. Visual Suggestion

6. Visual Suggestion

A flowchart illustrating the glass manufacturing process, highlighting sand as the primary input, the reaction pathways to produce glass, and the resultant products.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter on Materials.

Question 10 of 10 Authentic UPSC NDA Question

Which among the following is the popular method for manufacture of ammonia ?

Step-by-Step Logic & Solution

Correct Answer

βœ“ Option B is correct. The Haber-Bosch process is the primary industrial method for synthesizing ammonia.

πŸ“– Governing Law / Core Concept

The Haber-Bosch process is based on the principle of chemical equilibrium and the law of mass action, specifically utilizing the reaction:

\[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + \text{Heat} \]

πŸ§ͺ Step-by-Step Breakdown

In this exothermic reaction, nitrogen gas (Nβ‚‚) from the air and hydrogen gas (Hβ‚‚) from natural gas are combined at high temperatures (400-500Β°C) and pressures (150-200 atm) in the presence of a catalyst (usually iron). The key observations are:

  • The reaction shifts to produce more ammonia when heat is removed or pressure is increased.
  • The process yields a nitrogen to hydrogen molar ratio of 1:3.

πŸ” Option Analysis

  • A: Ostwald's Process - This method is used for nitric acid production, not ammonia.
  • C: Electric Furnace Process - Primarily used for producing silicon or phosphorous, not ammonia.
  • D: Electrolysis Process - Used in various chemical applications but is not a method for ammonia synthesis.

⚑ Mnemonic / Speed-Run

To remember the steps in the Haber-Bosch process: "Noble Hydrogen Meets Nitrogen Under Pressure" for Nitrogen (Nβ‚‚), Hydrogen (Hβ‚‚), Mixing, and Pressure.

6. Visual Suggestion

6. Visual Suggestion

A schematic diagram of the Haber-Bosch process showing gas flow from the nitrogen and hydrogen sources through the reactor, highlighting the catalyst placement and pressure conditions.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter on Chemical Thermodynamics and Industrial Chemistry.

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