Chemistry

Oxidation and Reduction Questions

Chapter: Chemical Reactions and Equations | Total Available: 13 Real Questions

Question 1 of 10 Authentic UPSC NDA Question

 Which one of the following is not an example ofa redox reaction?

Step-by-Step Logic & Solution

Correct Answer

✓ Option A is correct. It does not involve a change in oxidation states, hence, not a redox reaction.

📖 Core Concept

Redox reactions involve the transfer of electrons, leading to changes in oxidation states of reactants. The general equation governing redox reactions can be represented as:

Oxidation: \( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \)

Reduction: \( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \)

🧪 Step-by-Step Breakdown

The evaluation of each option determines if they are redox reactions:

  • Option A: AlCl₃ + 3H₂O → Al(OH)₃ + 3HCl
  • No change in oxidation states:

    Oxidation State of Al: +3 (both sides)

    Oxidation State of Cl: -1 (both sides)

  • Option B: 2NaH → 2Na + H₂
  • Redox Reaction:

    Oxidation: \( \text{Na}^{+} \rightarrow \text{Na}^0 \)

    Reduction: \( \text{H}^0 \rightarrow \text{H}_2 \)

  • Option C: 4Fe + 3O₂ → 2Fe₂O₃
  • Redox Reaction:

    Oxidation: \( \text{Fe}^0 \rightarrow \text{Fe}^{+3} \)

    Reduction: \( \text{O}_2^{0} \rightarrow \text{O}^{-2} \)

  • Option D: CuSO₄ + Zn → Cu + ZnSO₄
  • Redox Reaction:

    Oxidation: \( \text{Zn}^0 \rightarrow \text{Zn}^{+2} \)

    Reduction: \( \text{Cu}^{+2} \rightarrow \text{Cu}^0 \)

🔍 Option Analysis

Options B, C, and D are valid redox reactions as they involve changes in oxidation states, while Option A is an acid-base reaction (no change in oxidation states).

⚡ Mnemonic / Speed-Run

Mnemonic: "LEO says GER" — Lose Electrons Oxidation, Gain Electrons Reduction.

6. Visual Suggestion

6. Visual Suggestion

A comparison table showing each reaction and pointing out oxidation states for reactants and products would clarify the nature of redox reactions.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class 11 Chemistry, Chapter 8 (Redox Reactions).

Question 2 of 10 Authentic UPSC NDA Question

Which one of the following statements is NOT correct for the given reaction?

Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)

Step-by-Step Logic & Solution

Correct Answer

✓ Option C is correct. Copper is less reactive than iron.

📖 Governing Law / Core Concept

The reaction follows the principles of the reactivity series of metals. Iron displaces copper from copper sulfate solution, indicating that iron is more reactive.

🧪 Step-by-Step Breakdown

In the reaction:

\[ \text{Fe}(s) + \text{CuSO}_4(aq) \rightarrow \text{FeSO}_4(aq) + \text{Cu}(s) \]

Here, iron (Fe) oxidizes to Fe²⁺ and reduces Cu²⁺ to Cu. Thus:

  • Iron acts as a reducing agent.
  • The resulting solution of FeSO₄ turns green due to iron ions.
  • Copper is less reactive compared to iron.
  • This is a redox reaction.

🔍 Option Analysis

  • A: Iron is the reducing agent - correct.
  • B: The solution turns green - correct.
  • C: Copper is a more reactive metal than iron - incorrect.
  • D: It is a redox reaction - correct.

⚡ Mnemonic / Speed-Run

Remember, "Higher on the list, easier to displace" for reactivity series of metals.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XII Chemistry Chapter 7 (Redox Reactions).

Question 3 of 10 Authentic UPSC NDA Question

Hydrogenation of vegetable oils using nickel catalyst is an example of

Step-by-Step Logic & Solution

Correct Answer

✓ Option C is correct. The hydrogenation of vegetable oils is an addition reaction.

📖 Governing Law / Core Concept

In organic chemistry, an addition reaction involves the addition of one or more atoms or groups to a molecule without the loss of any atom from it.

🧪 Step-by-Step Breakdown

Vegetable oils, composed mainly of unsaturated fatty acids, undergo hydrogenation to form saturated fats. This process is typically represented by the equation:
\[ \text{C}_n\text{H}_{2n-2} + \text{H}_2 \xrightarrow{\text{Ni}} \text{C}_n\text{H}_{2n} \]
Here, \( \text{C}_n\text{H}_{2n-2} \) represents unsaturated fatty acids and \( \text{C}_n\text{H}_{2n} \) is the resultant saturated fatty acid (vegetable ghee). The nickel catalyst facilitates this addition by breaking the double bonds in the unsaturated hydrocarbons.

🔍 Option Analysis

- **A: Substitution reaction:** Involves the replacement of an atom in a molecule. - **B: Elimination reaction:** Involves the loss of atoms to form a double bond. - **D: Free-radical polymerization:** A process involving the reaction of monomers that form polymers.

⚡ Mnemonic / Speed-Run

Remember: "Addition is for hydrogenation!" to quickly recall that hydrogenation leads to addition reactions.

6. Visual Suggestion

6. Visual Suggestion

Consider a diagram showing the structure of vegetable oils (unsaturated) transitioning into vegetable ghee (saturated) through the process of hydrogenation, highlighting the breaking of double bonds.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XI Chemistry, Chapter on Organic Chemistry: Hydrocarbons.

Question 4 of 10 Authentic UPSC NDA Question

In the following redox reaction, which compound is acting as a reducing agent?

         N2H4 + 2H2O2 → N2 + 4H2O

Step-by-Step Logic & Solution

Correct Answer

✓ Option B is correct. N2H4 acts as the reducing agent by losing electrons.

📖 Governing Law / Core Concept

The reaction follows the principles of redox chemistry, where reducing and oxidizing agents are defined based on electron transfer. Here, N2H4 (hydrazine) undergoes oxidation while H2O2 (hydrogen peroxide) serves as the oxidizing agent.

🧪 Step-by-Step Breakdown

The given reaction:

\[ N_2H_4 + 2H_2O_2 \rightarrow N_2 + 4H_2O \]

Analyzing oxidation states:

  • Oxidation state of N in N2H4: -2
  • Oxidation state of N in N2: 0
  • Oxidation state of O in H2O2: -1
  • Oxidation state of O in H2O: -2

Change in oxidation states signifies:

  • From -2 (N2H4) to 0 (N2): N2H4 is oxidized.
  • O in H2O2 goes from -1 to -2: H2O2 is reduced.

Conclusion: N2H4 is acting as the reducing agent.

🔍 Option Analysis

  • H2O2: Acts as the oxidizing agent, gaining electrons.
  • N2: Product of reduction, not an agent.
  • H2O: Also a product, no redox role.

⚡ Mnemonic / Speed-Run

Remember: "OIL RIG" - Oxidation Is Loss, Reduction Is Gain. N2H4 loses electrons, hence it is oxidized.

6. Visual Suggestion

6. Visual Suggestion

A flowchart illustrating the electron transfer and changes in oxidation states during the reaction between N2H4 and H2O2 would clarify the redox processes involved, highlighting the roles of reducing and oxidizing agents.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter on Redox Reactions.

Question 5 of 10 Authentic UPSC NDA Question

Which one of the following statements regarding oxidation and reduction reaction is NOT correct?

Step-by-Step Logic & Solution
✓

1. Correct Answer

Option A is correct. The incorrect statement is that losing hydrogen refers to oxidation, not reduction.

📖 Short Explanation

The processes of oxidation and reduction involve changes in the gain or loss of elements like oxygen or hydrogen, or electrons. This question tests the conceptual understanding of how these reactions affect compounds.

💡 3. Why Correct Answer is Correct

Oxidation and reduction (redox reactions) are essential chemical reactions. Oxidation involves the gain of oxygen or the loss of hydrogen and electrons:
Oxidation: Loss of H2, Gain of O2
Reduction involves the gain of hydrogen or the loss of oxygen and gaining electrons:
Reduction: Gain of H2, Loss of O2

❌ 4. Why Other Options are Wrong

  • •Option B: This is correct. Loss of oxygen results in reduction (reducing the oxidation state).
  • •Option C: This is correct, gaining hydrogen leads to reduction.
  • •Option D: This is correct, gaining oxygen implies oxidation (increasing the oxidation state).
⚡

NDA Speed-Run / Mnemonic Shortcut

Use 'OIL RIG' as a mnemonic: "Oxidation Is Loss, Reduction Is Gain" of electrons.

🎯

5. Key Learning Point

Oxidation and reduction definitions: oxidation is loss of electrons/hydrogen or gain of oxygen; reduction is gain of electrons/hydrogen or loss of oxygen.

6. Visual Suggestion

A diagram illustrating a molecule, highlighting changes when it undergoes oxidation with oxygen atoms being attached, and reduction with hydrogen atoms being added or oxygen atoms being removed.

Question 6 of 10 Authentic UPSC NDA Question

Which one of the following oxides is a neutral oxide?

Step-by-Step Logic & Solution
✓

1. Correct Answer

Option A is correct. Carbon monoxide (CO) is a neutral oxide.

📖 Short Explanation

Neutral oxides are those oxides which neither show acidic nor basic properties. Carbon monoxide (CO) is an example of such neutral oxides.

💡 3. Why Correct Answer is Correct

Non-metal oxides can be either acidic or neutral. While carbon dioxide (CO2) is acidic, carbon monoxide (CO) is classified as a neutral oxide because it does not form acids or bases when reacted with water. It doesn't react with acids or bases to form salts, highlighting its neutral behavior.
CO + H2O ⇏ Acid/Base

❌ 4. Why Other Options are Wrong

  • •Option B: CO2 is an acidic oxide. It reacts with water to form carbonic acid (H2CO3).
  • •Option C: Na2O is a basic oxide. It reacts with water to form sodium hydroxide (NaOH).
  • •Option D: MgO is another basic oxide. It forms magnesium hydroxide (Mg(OH)2) when it reacts with water.
⚡

NDA Speed-Run / Mnemonic Shortcut

Remember “non-reactive, non-dissolved” to quickly identify neutral oxides like CO that neither show basic nor acidic properties in water.

🎯

5. Key Learning Point

Neutral oxides do not show characteristics of acids or bases and include compounds like CO and N2O.

6. Visual Suggestion

Create a Venn diagram categorizing metal and non-metal oxides into acidic, basic, amphoteric, and neutral types. Highlight examples like CO, N2O, and NO to visually explain their placement.

Question 7 of 10 Authentic UPSC NDA Question

What happens when the fat and oil-containing food materials are left outside for a long time?

Step-by-Step Logic & Solution
✓

1. Correct Answer

Option A is correct. Fats and oils in the food get oxidised.

📖 Core Concept

Rancidity is the oxidation process in fats and oils resulting in off-flavors and aromas when food is left exposed to air.

💡 3. Explanation

Oxidation is the primary cause of rancidity in which fatty acids react with oxygen leading to undesirable compounds such as aldehydes and ketones. The equation representing the process is as follows:
C₈H₁₈O₂ + O₂ → Rancid Compounds
The reaction is exacerbated by heat, light, and moisture leading to an enhanced rancid flavor profile.

❌ 4. Option Analysis

  • •Option B: Reduction doesn't occur in this context.
  • •Option C: Ice covering is irrelevant to food oxidation.
  • •Option D: Ignoring reaction contradicts the observed rancidity.
⚡

NDA Speed-Run / Mnemonic Shortcut

"Oil exposed leads to spoil, oxidation is the key to rancidity!"

🎯

5. Key Takeaways

Oxidation of fats and oils leads to rancidity, altering taste and quality.

Question 8 of 10 Authentic UPSC NDA Question

Which one of the following is an example of oxidation reaction?

Step-by-Step Logic & Solution

Correct Answer

✓ Option C is correct. Rusting of iron involves the oxidation of iron.

📖 Governing Law / Core Concept

Oxidation is a chemical process where a substance loses electrons, often increasing its oxidation state. The general reaction can be framed as:

\[ \text{Metal} + \text{O}_2 \rightarrow \text{Metal Oxide} \]

🧪 Step-by-Step Breakdown

In the rusting process, iron (Fe) reacts with oxygen (O2) and moisture to form iron(III) oxide (Fe2O3), commonly known as rust. The process can be outlined in steps:

  • Iron gets oxidized to ferrous ions (Fe2+):
  • \[ 4Fe + 3O_2 + 6H_2O \rightarrow 4Fe(OH)_3 \]
  • Ferrous ions further oxidize to ferric ions (Fe3+):
  • \[ 4Fe(OH)_3 \rightarrow 2Fe_2O_3 \cdot 3H_2O \]

The final product illustrates a characteristic reddish-brown color indicative of rust.

🔍 Option Analysis

  • A: Freezing of water - Physical change, no oxidation.
  • B: Dissolving sugar in water - Physical process, no electron transfer.
  • D: Boiling of petrol - Physical change, vaporization only.

⚡ Mnemonic / Speed-Run

For oxidation states, remember: "OIL RIG" (Oxidation Is Loss, Reduction Is Gain) to recall the electron transfer processes.

6. Visual Suggestion

A diagram illustrating the process of rust formation: show iron, water, and oxygen leading to the formation of Fe(OH)3 and subsequently Fe2O3. Include arrows indicating oxidation states and electron loss.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter on Oxidation and Reduction.

Question 9 of 10 Authentic UPSC NDA Question

Which one of the following processes is NOT part of chemical weathering ?

Step-by-Step Logic & Solution

Correct Answer

✓ Option (d) is correct. Thawing is a physical process, not chemical weathering.

📖 Governing Law / Core Concept

Chemical weathering encompasses processes that chemically alter minerals and rocks.

🧪 Step-by-Step Breakdown

Key processes of chemical weathering include:

  • Solution: Dissolution of minerals in water, e.g., NaCl (s) + H2O (l) → Na+ (aq) + Cl− (aq).
  • Hydration: Incorporation of water molecules into mineral structures, resulting in expansion.
  • Reduction: Loss of oxygen from minerals, e.g., 4Fe2O3 + 12C → 8Fe + 12CO.

In contrast, thawing is merely a phase change of ice melting into water, without chemical alteration of substances.

🔍 Option Analysis

  • A: Solution: Involves dissolving minerals, altering their chemical composition.
  • B: Hydration: Integrates water into the mineral structure, contributing to chemical changes.
  • C: Reduction: Reduces the oxidation state, affecting mineral composition.
  • D: Thawing: A physical transformation that does not affect mineral chemistry.

⚡ Mnemonic / Speed-Run

Remember: Chemical changes alter compositions (Solution, Hydration, Reduction), while physical changes reorganize states (such as Thawing).

6. Visual Suggestion

6. Visual Suggestion

A comparison chart illustrating chemical weathering processes (Solution, Hydration, Reduction) contrasted with Thawing as a physical weathering process, highlighting key characteristics and examples.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XI Environmental Science Chapter on Weathering Processes.

Question 10 of 10 Authentic UPSC NDA Question

Which one among the following oxides has thehighest melting point?

Step-by-Step Logic & Solution

Correct Answer

✓ Option (b) is correct. Magnesium oxide (MgO) has the highest melting point.

📖 Governing Law / Core Concept

The melting points of ionic compounds, predominantly influenced by their lattice energy, dictate their thermal stability. The relationship can be summarized as:

Stronger ionic bonds → Higher melting point.

🧪 Step-by-Step Breakdown

The melting points of the given oxides are:

  • Na2O: 1132°C
  • MgO: 2852°C
  • Fe2O3: 1565°C
  • CuO: 1326°C

MgO is an ionic compound with a significant lattice energy resulting from the strong electrostatic forces between Mg2+ and O2- ions. This leads to its high melting point, compared to the other oxides listed.

🔍 Option Analysis

Na2O, Fe2O3, and CuO possess ionic or covalent properties that contribute to lower melting points due to weaker ionic/covalent bonds or lattice structures.

⚡ Mnemonic / Speed-Run

Recall that magnesium (Mg) is in the period where ionic bonds (greater lattice energy) typically yield the highest melting points.

6. Visual Suggestion

6. Visual Suggestion

A comparative table showing the melting points and lattice energies of common oxides can aid in visualizing the relationships between ionic bonding strength and melting temperatures.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XII Chemistry, Chapter 4 (Chemical Bonding).

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