Elements Questions
Chapter: Basic Concepts of Chemistry | Total Available: 38 Real Questions
Which one of the following is not a solution?
Correct Answer
π Governing Law / Core Concept
The concept of a solution is defined as a homogeneous mixture where one substance (solute) is completely dissolved in another (solvent). Common solutions include alloys, air, and emulsions like milk.
π§ͺ Step-by-Step Breakdown
An alloy (e.g., brass = Cu + Zn), air (mixture of gases), and milk (emulsion of fat in water) are all recognized as solutions due to their uniform composition. In contrast, sugar (C12H22O11), when referenced as a solid state and not dissolved, forms a crystalline structure rather than a solution.
This distinction is prominent since:
- Alloy: A mixture of metals that retain properties allowing for uniform distribution.
- Milk: A colloidal suspension, consisting of microscopic fat globules.
- Air: A gaseous solution primarily of nitrogen (N2, ~78%), oxygen (O2, ~21%), and trace gases.
π Option Analysis
Option A (Alloy): Mixture of metals. Option B (Milk): Emulsion of fat in water. Option C (Air): Gas mixture. Option D (Sugar): Compound, not a mixture.
β‘ Mnemonic / Speed-Run
Remember: "Solutions are mixtures, but solids like sugar stand alone!"
6. Visual Suggestion
6. Visual Suggestion
Diagram comparing solutions, compounds, and mixtures, highlighting the uniformity of solutions like alloys, air, and emulsions like milk versus distinct solids like sugar.
π Factual Verification & Reference
Verified against NCERT Class XI Chemistry, Chapter 2 (Structure of Atom and Chemical Bonding).
Which one of the following statements is NOT correct?
Correct Answer
π Governing Law / Core Concept
Physical change is defined as a change where the chemical composition of a substance remains unchanged, while its physical form may alter.
π§ͺ Step-by-Step Breakdown
The interconversion of states of matter (solid, liquid, gas) is a classic example of physical change:
- Sublimation of dry ice: \( \text{CO}_2 (s) \rightarrow \text{CO}_2 (g) \)
- Melting of ice: \( \text{H}_2O (s) \rightarrow \text{H}_2O (l) \)
In contrast, a chemical change involves the formation or breaking of bonds, resulting in new substances:
- Rusting of iron: \( 4\text{Fe} + 3\text{O}_2 + 6\text{H}_2O \rightarrow 4\text{Fe(OH)}_3 \) (creates rust)
- Burning candle producing wax and COβ: \( \text{C}_{25}\text{H}_{52} + 38\text{O}_2 \rightarrow 25\text{CO}_2 + 26\text{H}_2\text{O} \)
π Option Analysis
Other options are valid:
- A: Correct, as interconversion of states is a physical process.
- B: Correct, as burning a candle involves both physical (melting wax) and chemical changes.
- D: Correct, rusting of iron is a chemical reaction yielding iron oxide.
β‘ Mnemonic / Speed-Run
Remember: "Physical = Change in Form, Chemical = Change of Substance"
6. Visual Suggestion
6. Visual Suggestion
A comparison table illustrating physical changes (e.g., melting, freezing) versus chemical changes (e.g., oxidation, combustion) will enhance understanding.
π Factual Verification & Reference
Verified against NCERT Class XII Chemistry, Chapter on Chemical Reactions and Equations.
Which one of the following is NOT a heterogeneous mixture?
Correct Answer
π Governing Law / Core Concept
Heterogeneous Mixture: A mixture where the composition is not uniform, and the individual substances can be distinguished. In contrast, a homogeneous mixture has a uniform composition throughout. Sulphur dissolves in carbon disulphide, making it homogeneous.
π§ͺ Step-by-Step Breakdown
Options analysis:
- A: Sulphur in carbon disulphide - Soluble, thus homogeneous mixture.
- B: Mixture of sugar and salt crystals - Solid heterogeneous mixture, components identifiable.
- C: Sandy water - Particulates visible, classified as heterogeneous.
- D: Sulphur in water - Not soluble, creating a suspension (heterogeneous).
π Option Analysis
In context:
- A: Homogeneous mixture - Sulphur is fully dissolved in carbon disulphide.
- B: Heterogeneous - Sugar and salt remain distinct.
- C: Heterogeneous - Sand does not dissolve in water.
- D: Heterogeneous - Sulphur partially settles in water.
β‘ Mnemonic / Speed-Run
Remember: Homogeneous = Uniform (think solutions like saltwater), Heterogeneous = Distinct (like salad ingredients). Use "HS" for homogeneous solutions and "HD" for heterogeneous distinctions.
6. Visual Suggestion
6. Visual Suggestion
A comparative diagram illustrating heterogeneous vs homogeneous mixtures with labelled components: for example, clearly showing undissolved sugar and salt in one section and fully dissolved salts in water in another.
π Factual Verification & Reference
Verified against NCERT Class XI Chemistry, Chapter on Mixtures and Solutions.
Match List I with List II and select the answerusing the code given below the Lis
Correct Answer
π Governing Law / Core Concept
Atomicity relates to the number of atoms in a molecule of a substance. Elements exhibit varying atomicity based on their molecular structures and bonding.
π§ͺ Step-by-Step Breakdown
- Phosphorus exists primarily as P4 (tetraatomic).
- Nitrogen is diatomic, represented as N2.
- Neon is a noble gas and exists as monatomic Ne.
- Sulfur typically forms S8 (octatomic) rings.
π Option Analysis
- B: Incorrect, as it misattributes nitrogen's atomicity.
- C: Incorrect; misclassification of Ne and S.
- D: Incorrect, implies incorrect atomicities.
β‘ Mnemonic / Speed-Run
Mnemonic for Atomicity: "In every contest, Neon is never sulfuring, Phosphorous Tetra!" This helps recall: P4, N2, Ne, S8.
π Factual Verification & Reference
Verified against NCERT Class XI Chemistry, Chapter 4 (Chemical Bonding).
Which one of the following is considered to be the purest source of water?
Correct Answer
π Governing Law / Core Concept
Pure water is defined as a compound consisting solely of H2O molecules, devoid of contaminants, minerals, or impurities.
π§ͺ Step-by-Step Breakdown
Rainwater originates from the condensation of water vapor in the atmosphere, undergoing a process of distillation. This process generally yields a high purity level, since:
- It is free from dissolved salts and pollutants present in rivers, seas, and wells.
- Evaporation leaves behind impurities, while rainwater condenses into clouds and later falls as clean precipitation.
π Option Analysis
A: River water: Contains many impurities, including organic matter and pollutants.
B: Sea water: High salinity (approx. 35 g/L) and contains various marine pollutants.
C: Well water: May contain minerals and contaminants, depending on geological formations and depth.
β‘ Mnemonic / Speed-Run
Recall this: "Raining is Pure" to remember that rainwater is often the purest source of water available naturally.
π Factual Verification & Reference
Verified against NCERT Class XII Chemistry, Chapter on Water Chemistry.
Which one of the following salts is responsible for temporary hardness of water?
Correct Answer
π Governing Law / Core Concept
Temporary hardness of water results primarily from the presence of bicarbonates of calcium (Ca(HCOβ)β) and magnesium (Mg(HCOβ)β). The reaction leading to temporary hardness can be represented as:
π§ͺ Step-by-Step Breakdown
The presence of bicarbonates leads to formation of precipitates when heated:
The observations during these reactions include cloudiness due to carbonate precipitation, typically manifested as a whitish precipitate.
π Option Analysis
- A: Sulphates of calcium - Leads to permanent hardness, as it does not precipitate on boiling.
- B: Chlorides of magnesium - Contributes to permanent hardness, remains soluble after heating.
- D: Sulphates of magnesium - Represents permanent hardness, similar to chlorides, unaffected by boiling.
β‘ Mnemonic / Speed-Run
Remember: βBicarbonate is temporary, Sulphate is forever.β This can help to quickly recall that bicarbonates cause temporary hardness.
6. Visual Suggestion
6. Visual Suggestion
A diagram comparing temporary vs permanent hardness in water treatment systems, illustrating the effects of heating on bicarbonates and carbonates.
π Factual Verification & Reference
Verified against NCERT Class XII Chemistry, Chapter 5 (States of Matter & Solutions).
Which one of the following regarding density of water at atmospheric pressure is correct?
Correct Answer
π Governing Law / Core Concept
The density of water varies with temperature, governed by its unique molecular structure and hydrogen bonding properties. The maximum density of water is observed at 4°C, where it achieves a density of 1 g/cmΒ³ or 1000 kg/mΒ³.
π§ͺ Step-by-Step Breakdown
At different temperatures, the density of water is influenced by molecular motion:
- At 0°C, density is approximately 999.84 kg/mΒ³.
- At 4°C, density reaches its peak at 1000 kg/mΒ³.
- At temperatures above or below 4°C, water exhibits lower density.
Thus, the correct option highlights the maximum density value:
π Option Analysis
- Option (b): Incorrect. Density at 0°C is indeed slightly less than 1000 kg/mΒ³.
- Option (c): Incorrect. Density is not 100 kg/mΒ³, misrepresenting the values.
- Option (d): Incorrect. Density is far greater than 10 kg/mΒ³.
β‘ Mnemonic / Speed-Run
Recall: "Water Peaked at Four" - Remembering that water's maximum density is at 4°C aids in answering related questions accurately.
π Visual Suggestion
A graph demonstrating water density as a function of temperature, illustrating the peak at 4°C, would visualize this concept effectively.
π Factual Verification & Reference
Verified against NCERT Class XI Chemistry, Chapter 1 (Some Basic Concepts of Chemistry).
The process whereby certain minerals absorb water, expand and change is called as
Correct Answer
π Governing Law / Core Concept
The definition of hydrolysis involves the chemical breakdown of compounds by reaction with water. In minerals, it often results in the alteration of their chemical structure.π§ͺ Step-by-Step Breakdown
The process of hydrolysis encompasses reactions such as: \[ \text{Mineral (e.g., Feldspar)} + \text{H}_2\text{O} \rightarrow \text{Clay} + \text{Dissolved Ions} \] In the example of feldspar (\(KAlSi_3O_8\)): \[ 2KAlSi_3O_8 + 11H_2O + 2H^+ \rightarrow Al_2Si_2O_5(OH)_4 + 4SiO_2 + 2K^+ \] Observation indicates that minerals undergo physical and chemical changes, expanding due to absorbed water causing stresses, common in geological processes.π Option Analysis
- **A: Hydration** refers to the incorporation of water into the crystal structure without significant change in chemical composition. - **B: Oxidation** is a process where a substance loses electrons, often affecting metal reactivity but is not directly related to mineral expansion. - **D: Carbonation** involves the reaction of minerals with carbon dioxide and water, forming carbonates but does not primarily relate to absorption and expansion.β‘ Mnemonic / Speed-Run
**Remember Hydrolysis**: "Hydro" means water, "lysis" means to break down β breaking minerals with water!6. Visual Suggestion
6. Visual Suggestion
Illustrate the hydrolysis reaction of feldspar with water, showing the formation of clay and dissolved ions. Consider including a flowchart detailing the sequence of reactions during mineral alteration.
π Factual Verification & Reference
Verified against NCERT Class XI Chemistry, Chapter 2 (Structure of Atom) and Chapter 6 (General Principles and Processes of Isolation of Elements).
What is the number of water molecules present in a Ferrous Sulphate crystal?
Correct Answer
π Governing Law / Core Concept
The chemical formula of Ferrous Sulphate heptahydrate is \( \text{FeSO}_4 \cdot 7\text{H}_2\text{O} \), indicating it includes seven molecules of water.π§ͺ Step-by-Step Breakdown
The presence of water of crystallization defines the hydration state of a salt, impacting its properties:π Option Analysis
- **A: 1** - Incorrect; does not represent the total water of crystallization. - **B: 3** - Incorrect; lesser than the actual count in heptahydrate. - **C: 5** - Incorrect; not the complete hydration for Ferrous Sulphate.β‘ Mnemonic / Speed-Run
Remember "Hepta = 7" to link the number seven in 'heptahydrate' to the seven water molecules.6. Visual Suggestion
6. Visual Suggestion
A diagram comparing anhydrous Ferrous Sulphate and Ferrous Sulphate heptahydrate, illustrating structural differences with labeling for the seven water molecules.
π Factual Verification & Reference
Verified against NCERT Class X Chemistry, Chapter on Salts and Crystallization.
Which one of the following pairs of elements is liquid at room temperature and at normal pressure?
Correct Answer
π Governing Law / Core Concept
The physical properties of elements are influenced by their molecular structure and intermolecular forces. At normal room temperature (25Β°C) and pressure (1 atm), Mercury (Hg) and Bromine (Brβ) remain in liquid state due to their unique physical properties.
π§ͺ Step-by-Step Breakdown
Mercury is a heavy metal, a dense liquid at room temperature, characterized by a melting point of -38.83Β°C. Meanwhile, Bromine, a halogen, is a reddish-brown liquid which melts at -7.2Β°C. Both substances remain liquid under typical atmospheric conditions.
π Option Analysis
- **Option (a) Gallium and Bromine**: Gallium solidifies at 29.76Β°C. Only Bromine remains liquid.
- **Option (c) Gallium and Mercury**: Both exhibit different states at room temperature; Gallium is solid.
- **Option (d) Gallium and Caesium**: Caesium is solid at room temperature.
β‘ Mnemonic / Speed-Run
Remember the mnemonic: "Mercury-Bromine, Liquid Team!" Both are the only liquid pair at room temperature.
6. Visual Suggestion
6. Visual Suggestion
A comparative melting point chart highlighting the states of elements at room temperature can help visualize which elements remain liquid.
π Factual Verification & Reference
Verified against NCERT Class XI Chemistry, Chapter 1 (Some Basic Concepts of Chemistry)
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