Parallelogram of forces Practice Questions

Question 1 of 1 NDA MCQ

Two forces of 5.0 N each are acting on a point mass. If the angle between the forces is 60°, then the net force acting on the point mass has magnitude close to ?

Detailed Explanation

Solution

Option (a) is correct.

Explanation:

\[ F_{net} = \sqrt{F_1^2 + F_2^2 + 2F_1F_2\cos\theta} \]

\[ F_{net} = \sqrt{(5.0)^2 + (5.0)^2 + 2 \cdot 5.0 \cdot 5.0 \cdot \cos 60^\circ} \]

\[ F_{net} = \sqrt{25 + 25 + 25} \]

\[ F_{net} = \sqrt{75} \approx 8.66 \, \text{N} \]

📌 Hints / Properties Used:

Vector Addition of Forces
Cosine Rule: \( c^2 = a^2 + b^2 - 2ab\cos(\theta) \)

📊 Visual Diagram Suggestion:

A force diagram displaying two vectors of equal length (5.0 N) separated by a 60° angle will clearly illustrate the resultant vector, allowing students to visualize vector addition in action.

📖 Factual Verification & Reference:

Verified against NCERT Class XI Physics, Chapter 4 (Motion in a Plane)

Parallelogram of forces

Solution

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