Physics

Use of X-rays

Chapter: Modern Physics & Applications

Question 1 of 3 NDA MCQ

Which one of the following wavelengths corresponds to the wavelength of X–rays?

Detailed Explanation

Correct Answer

βœ“ Option (d) is correct. The wavelength of X-rays is typically between 0.1 nm and 10 nm.

πŸ“– Governing Law / Core Concept

The electromagnetic spectrum includes X-rays, which are characterized by short wavelengths typically in the range of:

\[ \text{Wavelength of X-rays } \approx 0.1 \, \text{nm} \text{ to } 10 \, \text{nm} \]

πŸ§ͺ Step-by-Step Breakdown

X-rays are high-energy electromagnetic radiation produced when electrons are decelerated upon striking a metal target:

  • For range consideration, X-rays have wavelengths less than visible light, which ranges from approximately 400 nm to 700 nm.
  • Therefore, any wavelength above 10 nm does not classify as X-ray.
  • Among the options presented:
    • A: 500 nm (Visible light)
    • B: 5000 nm (Infrared)
    • C: 100 nm (Ultraviolet)
    • D: 1 nm (X-ray)

πŸ” Option Analysis

Analysis of incorrect options:

  • A: 500 nm - Falls within the visible spectrum.
  • B: 5000 nm - Falls within the infrared spectrum.
  • C: 100 nm - While close, it is positioned in the ultraviolet range.

⚑ Mnemonic / Speed-Run

Remember: X-rays are "extremely short", rhyme with "X-rays" and think of a nanometer scale.

6. Visual Suggestion

6. Visual Suggestion

Consider a schematic diagram illustrating the electromagnetic spectrum, highlighting the position of X-rays (0.1 nm to 10 nm) alongside visible light and infrared sections.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Physics Class 12, Chapter 10 (Wave Optics).

Question 2 of 3 NDA MCQ

Which one of the following statements about X-rays is not true ?

Detailed Explanation

Correct Answer

βœ“ Option (c) is correct. X-rays cannot be utilized for radar systems due to their distinct operational principles and the nature of their wavelengths.

πŸ“– Governing Law / Core Concept

X-rays are a form of electromagnetic radiation with wavelengths ranging from 0.01 to 10 nanometers. Unlike radar, which operates on microwaves (wavelengths of 1 mm to 1 m), X-rays are primarily generated when high-energy electrons collide with a metal target, leading to energy emission in the X-ray range.

πŸ§ͺ Step-by-Step Breakdown

1. Wavelength of X-rays: \[ \text{Typical Wavelength} \approx 1 \, \text{Γ…} = 1 \times 10^{-10} \text{m} \] 2. Production Mechanism: When high-energy electrons strike a target material (e.g., tungsten), they decelerate rapidly, producing X-ray photons through: \[ \text{Energy} = h \cdot f \] where \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)), and \( f \) is the frequency of the emitted radiation. 3. Distinct from Radar: Radar systems utilize longer wavelengths (microwaves), unsuitable for dispersing X-ray radiation.

πŸ” Option Analysis

- Option A: True. X-rays have wavelengths of about 1 Γ…. - Option B: True. Generated via electron bombardment of metals. - Option C: False. X-rays are not used for radar systems. - Option D: True. X-rays are utilized in cancer treatment, such as radiotherapy.

⚑ Mnemonic / Speed-Run

Remember: X-rays = X-tremely short wavelengths; Radar = Requires longer wavelengths.

6. Visual Suggestion

6. Visual Suggestion

A schematic of X-ray production illustrating the electron collision with a tungsten target, highlighting the emitted X-ray photons and their wavelength compared to radar waves.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Physics, Chapter 9 (Optics).

Question 3 of 3 NDA MCQ

Which one of the following wavelength radiations may correspond to an X-ray?

Detailed Explanation

Correct Answer

βœ“ Option A is correct. X-rays typically range from about 0.01 nm to 10 nm.

πŸ“– Governing Law / Core Concept

The electromagnetic spectrum categorizes radiation based on wavelength. X-rays occupy the range approximately from \(0.01 \, \text{nm}\) to \(10 \, \text{nm}\).

πŸ§ͺ Step-by-Step Breakdown

The formula relating energy \(E\) to wavelength \(\lambda\) is given by:

\[ E = \frac{hc}{\lambda} \]

Where:
\(E\) = energy in Joules (J)
\(h\) = Planck's constant \( (6.626 \times 10^{-34} \, \text{J.s}) \)
\(c\) = speed of light \( (3 \times 10^8 \, \text{m/s}) \)
\(\lambda\) = wavelength in meters (m)

Using this, we can estimate energies associated with the options. For instance, at \( \lambda = 1 \, \text{nm} = 1 \times 10^{-9} \, \text{m} \):

\[ E = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{1 \times 10^{-9}} = 1.986 \times 10^{-14} \, \text{J} \approx 124 \, \text{keV} \]

This energy is characteristic of X-ray photons.

πŸ” Option Analysis

Other options include:

  • Option B (10 nm): Also in X-ray range but at the upper threshold.
  • Option C (100 nm): Falls into the ultraviolet (UV) spectrum.
  • Option D (300 nm): Clearly in the UV spectrum.

⚑ Mnemonic / Speed-Run

Remember: X-ray wavelengths are \(0.01 - 10 \, \text{nm}\). X-rays = eXtreme radiations (short wavelength).

6. Visual Suggestion

6. Visual Suggestion

A diagram illustrating the electromagnetic spectrum, highlighting the X-ray region with specific wavelength indicators (0.01 to 10 nm) compared to other regions like UV and visible light.

πŸ“– Factual Verification & Reference

πŸ“– Factual Verification & Reference:

Verified against NCERT Class XII Physics, Chapter on Wave Optics.

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