Chapter: Statistics and Probability
The variance of five positive observations is 3.6. If four of the observations are 2, 2, 4, 5 then what is the remaining observation?
Explanation:
Let x be the 5th observation
∴ Variance = (2² + 2² + 4² + 5² + x²)/5 − ((2 + 2 + 4 + 5 + x)/5)²
3.6 = (49 + x²)/5 − (13 + x)²/25
⇒ 3.6 × 25 = 5(49 + x²) − (13 + x)²
⇒ 90 = 245 + 5x² − 169 − x² − 26x
⇒ 2x² − 13x − 7 = 0
⇒ x = 7, x = −1/2
(∵ observation is positive)
∴ x = 7
If two random variables X and Y are connected by relation 2X-3Y/5X+4Y = 4 and X follows Binomial distribution with parameters n = 10 and p = 1/2 , then what is the variance of Y?
Consider the following for the next two (02) items that follow:
The marks obtained by 10 students in a Statistics
test are 24, 47, 18, 32, 19, 15, 21, 35, 50 and 41
What is the variance of the largest five observations?
Direction for Questions (95-96): Consider the following for the two (02) items that follow: The sum and the sum of squares of the observation corresponding to length X (in cm) and weight Y (in gm) of 50 tropical tubers are given as ∑X = 200, ∑Y = 250, ∑X2 = 900 and ∑Y2 = 1400.
Which of the following is correct?
If the random variable X has mean 3 and standard deviation 5, then what is the variance of the random variable
Y = 2X − 5 ?
Option (d) is correct.
Explanation:
A flowchart illustrating the transformation of the random variable X to Y, showing how mean and variance transform under linear transformations.
Verified against standard statistical principles (e.g., NCERT Class XI Mathematics, Chapter on Statistics).
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