Human eye Questions
Chapter: Optics | Total Available: 11 Real Questions
Human eye can see objects at different distances with contrasting illuminations. This is due to
Correct Answer
📖 Governing Law / Core Concept
The ability of the human eye to focus on objects at varying distances is governed by the principle of accommodation, which is the eye's ability to change its focal length to see nearby and distant objects clearly. The formula for the power of the lens is given by:
Where \( P \) is the power of the lens in diopters (D), and \( f \) is the focal length in meters (m).
🧪 Step-by-Step Breakdown
When we switch focus from a distant object to a near object:
Here, the ciliary muscles adjust the lens shape to increase the curvature, thus increasing \( P \). For instance:
This results in sharper images for closer objects.
🔍 Option Analysis
- A: Far-sightedness - A condition where distant objects are seen more clearly than near ones due to a shorter eyeball or flat lens.
- B: Near-sightedness - A condition where near objects are visible, but distant objects appear blurry due to an elongated eyeball or overly curved lens.
- C: Far-sightedness and near-sightedness - Both conditions hinder normal accommodation, but they are not the mechanism by which the eye focuses.
⚡ Mnemonic / Speed-Run
Remember: "Accommodation Adjusts" to recall the function of the eye in focusing.
6. Visual Suggestion
6. Visual Suggestion
A ray diagram depicting accommodation should illustrate the lens shape changing while focusing on a nearby object, contrasting with its shape for distant objects.
📖 Factual Verification & Reference
Verified against NCERT Class 11 Physics, Chapter 10 (Light).
Myopia is a defect in human vision where an image of a
Correct Answer
📖 Governing Law / Core Concept
Myopia (or nearsightedness) is a condition governed by the principles of lens optics. It occurs when the eye is too long or the cornea is too curved, resulting in light rays from distant objects converging before reaching the retina.🧪 Step-by-Step Breakdown
In myopia, the focal length \( f \) of the eye's lens system is shorter than normal, leading to the following optical formula: \[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \] where: - \( f \) = focal length (m), - \( d_o \) = object distance (m), - \( d_i \) = image distance (m; negative for virtual image in myopia). For distant objects (large \( d_o \)), \( d_i \) becomes negative, indicating the image is formed before the retina. Thus: \[ d_i < 0 \quad (myopia) \] As a result, distant images appear blurry due to improper focus.🔍 Option Analysis
- **Option A**: Incorrect, as nearby objects are focused correctly on the retina. - **Option B**: Incorrect, nearby objects focus well; this describes hyperopia. - **Option D**: Incorrect, distant objects are not focused beyond the retina.⚡ Mnemonic / Speed-Run
Remember **"Myopic eyes miss distant views"** to recall that myopia affects the ability to see distant objects clearly.6. Visual Suggestion
6. Visual Suggestion
A ray diagram illustrating the focal points of a myopic eye shows rays from distant objects converging before the retina, creating a blurry image instead of reaching it directly.
📖 Factual Verification & Reference
Verified against NCERT Class XII Physics, Chapter on Optics.
A person can see nearby objects clearly but cannot see distant object distinctly, the person is suffering with
Correct Answer
📖 Governing Law / Core Concept
The condition described is governed by the concept of refraction and the ability of the eye to focus light. For a person with myopia (nearsightedness), the image of distant objects is focused in front of the retina.
🧪 Step-by-Step Breakdown
In myopia, the far point of vision is reduced due to excessive curvature of the lens or elongation of the eyeball. The equation governing this can be represented as:
Where:
- f = focal length (in meters)
- d_o = object distance (in meters)
- d_i = image distance (in meters)
In nearsightedness, the focal length (f) is negative due to virtual image formation. Therefore, the individual's eye cannot correctly project light from distant objects to the retina.
🔍 Option Analysis
- Option A: Hypermetropia - Difficulty seeing near objects, vision is clear for distant objects.
- Option B: Presbyopia - Age-related condition affecting near vision, associated with loss of elasticity of the lens.
- Option D: None of above - Incorrect as myopia (Option C) is indeed the relevant condition.
⚡ Mnemonic / Speed-Run
To remember myopia, think: "My Eye Peers At Nearby," emphasizing the focus on near objects over distant objects.
6. Visual Suggestion
6. Visual Suggestion
A ray diagram illustrating myopia would show parallel rays from a distant object converging before reaching the retina, demonstrating the need for corrective lenses.
📖 Factual Verification & Reference
Verified against NCERT Class XII Physics, Chapter 10 (Ray Optics and Optical Instruments)
Which one of the following is correct for a person suffering from myopia?
Correct Answer
📖 Governing Law / Core Concept
Myopia, or nearsightedness, is a refractive error in which light entering the eye focuses in front of the retina due to the eyeball being too long or the lens being too curved.
🧪 Step-by-Step Breakdown
In myopia:
- Light rays from distant objects converge before reaching the retina, causing blurred vision for faraway items.
- Objects closer than the focal point are clearly perceived.
Corrective measures include:
- Using concave lenses to diverge incoming light rays, which moves the focal point back onto the retina.
🔍 Option Analysis
Option (B): Incorrect. A myopic person has difficulty seeing distant objects.
Option (C): Incorrect. Color vision is typically not associated with myopia.
Option (D): Incorrect. Myopic individuals can see nearby objects clearly, unlike distant ones.
⚡ Mnemonic / Speed-Run
Mnemonic for myopia: "M" for "Myopic" means "My Eyes Are Perfect for the Close!"
6. Visual Suggestion
A ray diagram illustrating the path of light rays from near and far objects through a concave lens would clarify the condition of myopia and its correction.
Verified against NCERT Class 12 Physics, Chapter on Optics.
For a human eye, where u is the distance of anobject from the eye, f is the focal length of thelens and v is the distance of image from the eye,which is the correct schematic graph?
Correct Answer
📖 Governing Law / Core Concept
The fundamental principle is derived from the lens formula for a thin lens, given by:🧪 Step-by-Step Breakdown
As the object distance \( u \) increases, the following observations are noted: 1. For closer objects, \( |u| \) is small, leading to a larger \( |v| \) as per the lens formula. 2. As \( u \) increases, \( v \) should also increase but initially at a decreasing rate, indicating that \( f \) might vary. 3. At very large \( u \), \( f \) approaches a constant value, reflecting the behavior depicted in the provided graphs. This behavior aligns with option (c) graphically, as shown below:🔍 Option Analysis
- Option A: Incorrect, as it depicts a linear relationship not supported by the lens formula. - Option B: Incorrect, it represents an incorrect graph form of the relationship between \( u \) and \( v \). - Option D: Incorrect, it does not provide a realistic depiction of how \( f \) reacts to changes in \( u \).⚡ Mnemonic / Speed-Run
The relationship can be remembered with the phrase "Focal functions finely" indicating that as object distance increases, focal length optimally adjusts until it levels off.6. Visual Suggestion
6. Visual Suggestion
Incorporate a graph illustrating \( v \) vs \( u \), indicating initial steepness which flattens as \( u \) increases. This visual would significantly aid in understanding the relationship.
📖 Factual Verification & Reference
Verified against NCERT Class XII Physics, Chapter 9 (Optics).
The human eye is like a camera that has a lenswith:
Correct Answer
📖 Governing Law / Core Concept
The human eye operates based on the principles of optics, specifically the laws concerning lenses. The eye's lens changes shape to focus light, while the pupil adjusts to control light intake, much like a camera lens and aperture system.
🧪 Step-by-Step Breakdown
The human eye focuses on objects at varying distances through a process called accommodation:
The eye’s lens adjusts its curvature to change the focal length, denoted as \(f\), where closer objects result in a shorter \(f\) (more curvature) and vice versa.
The adjustment of the pupil is dictated by light intensity, allowing the eye to modulate light entry through the following relation:
🔍 Option Analysis
- Option A: Fixed focal length and aperture size. Incorrect, as the eye cannot adjust these parameters.
- Option B: Variable focal length, fixed aperture size. Incorrect, since the pupil size also changes.
- Option C: Fixed focal length, variable aperture size. Incorrect; the lens must adjust for focus.
⚡ Mnemonic / Speed-Run
VAF: Variable Aperture, Variable Focal length – a reminder that the eye dynamically accommodates both light intensity and focusing distance.
6. Visual Suggestion
Visualize a ray diagram where rays from various distances converge onto the retina, demonstrating how the lens changes shape to maintain focus, and how the pupil constricts or dilates in response to light conditions.
📖 Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter 10 (Light: Reflection and Refraction)
Ramesh cannot see distinctly objects kept beyond 2 m. This defect can be corrected by using a lens of power
Sita, 1·5 m high, stands before a plane mirror fixed on a wall to view her full image. What should be the minimum height of the plane mirror so that Sita can view her image fully?
Explanation: In order to see the full image, the size of mirror required is just half of the height of object. the minimum height of the plane mirror required is h = 1.5 /2 = 0.75 m
The part of the human eye on which the image is formed is
Correct Answer
📖 Governing Law / Core Concept
The retina contains photoreceptor cells (rods and cones) that detect light and convert it into electrical signals, which are sent to the brain to form images.🧪 Step-by-Step Breakdown
Light enters the eye through the cornea, passes through the pupil, and is focused by the lens onto the retina. The retina processes the light and sends signals via the optic nerve. \[ \text{Image Formation: } \text{Light} \rightarrow \text{Cornea} \rightarrow \text{Pupil} \rightarrow \text{Lens} \rightarrow \text{Retina} \]🔍 Option Analysis
- **A: Pupil** - The opening in the iris that regulates the amount of light entering the eye. - **B: Cornea** - The transparent layer covering the front of the eye, responsible for light refraction. - **D: Iris** - The colored part of the eye that controls the size of the pupil.⚡ Mnemonic / Speed-Run
Remember: "CRISP" - Cornea > Retina > Image formation > Signals > Perception (via optic nerve).6. Visual Suggestion
Illustrate a ray diagram showing light entering the eye, highlighting the path through the cornea, pupil, and lens, converging on the retina.
📖 Factual Verification & Reference
Verified against NCERT Class XII Biology, Chapter 20 (Human Eye).
Light enters the eye through a thin membrane called
Correct Answer
📖 Governing Law / Core Concept
The process of light entering the human eye is primarily governed by the principles of optics. The cornea acts as the initial medium through which light travels, due to its refractive properties.🧪 Step-by-Step Breakdown
The cornea is a transparent layer covering the front of the eye. - **Refraction at the Cornea:** The cornea has a refractive index of approximately 1.376. When light passes from air (\( n \approx 1.000 \)) into the cornea, it bends as per Snell's Law: \[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \] Where: - \( n_1 = 1.000 \) (air) - \( n_2 = 1.376 \) (cornea) - \( \theta_1 \) = angle of incidence - \( \theta_2 \) = angle of refraction This initial refraction is essential for focusing light onto the retina.🔍 Option Analysis
- **A: Retina** - The retina is located at the back of the eye where images are formed. - **C: Pupil** - The pupil is the opening that allows light to enter but is not a membrane. - **D: Iris** - The iris controls the size of the pupil but does not allow light entry.⚡ Mnemonic / Speed-Run
Remember: **C**ornea **F**irst - The **c**ornea is the first layer light interacts with before entering the eye.6. Visual Suggestion
6. Visual Suggestion
Illustrate a ray diagram showing light entering the eye through the cornea, indicating refraction and interaction with the pupil and lens leading to the retina.
📖 Factual Verification & Reference
Verified against NCERT Class 11 Physics, Chapter 10 (Light).
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