Physics

Spherical mirrors and lenses

Chapter: Optics

Question 1 of 5 NDA MCQ

 What is the magnification produced by aconcave lens of focal length 10 cm, when animage is formed at a distance of 5 cm from thelens?

Detailed Explanation

Solution

Option (c) is correct.

Explanation:

\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]
Given:
  • Focal length, \( f = -10 \) cm (concave lens is negative)
  • Image distance, \( v = -5 \) cm (image on the same side as the object)
Using the lens formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Substituting the known values: \[ \frac{1}{-10} = \frac{1}{-5} + \frac{1}{u} \] Calculating \( \frac{1}{u} \): \[ \frac{1}{u} = \frac{1}{-10} - \frac{1}{-5} \] \[ \frac{1}{u} = -0.1 + 0.2 = 0.1 \implies u = 10 \text{ cm} \] Now, use the magnification formula: \[ M = \frac{-v}{u} \] Substituting the values: \[ M = \frac{-(-5)}{10} = \frac{5}{10} = 0.5 \] Thus, the magnification produced is \( 0.5 \).
๐Ÿ“Œ Hints / Properties Used:
  • Lens formula: \( \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \)
  • Magnification formula: \( M = \frac{-v}{u} \)
๐Ÿ“Š Visual Diagram Suggestion:

A ray diagram depicting a concave lens, indicating the object at 10 cm on the left, the image formed at -5 cm on the left, and the relationships amongst u, v, and f with corresponding light rays diverging from the focal point.

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class XII Physics, Chapter 6 (Optics)

Question 2 of 5 NDA MCQ

Spherical mirror formula relating an object distance u, image distance v and focal length of mirror f may be applied to a plane mirror when

Detailed Explanation

Correct Answer

โœ“ Option (a) is correct. A plane mirror is a spherical mirror with an infinite focal length.

๐Ÿ“– Governing Law / Core Concept

The spherical mirror formula is given by:
\[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \]
Where:
  • \( f \) = focal length (m)
  • \( u \) = object distance (m)
  • \( v \) = image distance (m)
In the case of a plane mirror, the focal length approaches infinity, leading to an equal distance of the object and image from the mirror surface.

๐Ÿงช Step-by-Step Breakdown

For a plane mirror, we consider the limit as follows: As \( f \to \infty \):
\[ \lim_{f \to \infty} \frac{1}{f} = 0 \]
Substituting in the mirror formula, we have:
\[ 0 = \frac{1}{u} + \frac{1}{v} \]
This leads us to \( v = -u \), indicating that distances are equal and both are on opposite sides of the mirror.

๐Ÿ” Option Analysis

- **B**: Focal length goes to zero - Incorrect, as this would imply the mirror does not converge rays. - **C**: Image distance goes to zero - Incorrect, as it would mean the image is at the mirror surface. - **D**: Image distance goes to infinity - Incorrect, as an infinite image distance is contradictory for a plane mirror.

โšก Mnemonic / Speed-Run

Remember that **Plane Mirror = Infinite Focal Length**. It helps to recall that light reflects off a plane mirror without convergence.

6. Visual Suggestion

6. Visual Suggestion

A ray diagram illustrating a plane mirror which shows parallel rays reflecting back at equal angles, demonstrating that the object and the image are equidistant from the mirror surface.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class XII Physics, Chapter on Ray Optics.

Question 3 of 5 NDA MCQ

Power of a lens of focal length 25 cm is

Detailed Explanation

Correct Answer

โœ“ Option (c) is correct. The power of the lens is +4 Dioptre.

๐Ÿ“– Governing Law / Core Concept

The power \( P \) of a lens is given by the formula:
\[ P = \frac{1}{f} \]
where \( P \) is the power in Dioptres (D) and \( f \) is the focal length in meters (m).

๐Ÿงช Step-by-Step Breakdown

Given \( f = 25 \) cm, convert to meters:
\[ f = \frac{25}{100} = 0.25 \, m \]
Substituting into the power formula:
\[ P = \frac{1}{0.25} \]
Calculating:
\[ P = 4 \, D \]

๐Ÿ” Option Analysis

- Option (a): +2.5 Dioptre - Incorrect, as \( P = 4 \). - Option (b): +3 Dioptre - Incorrect, as \( P = 4 \). - Option (d): +5 Dioptre - Incorrect, as \( P = 4 \).

โšก Mnemonic / Speed-Run

To remember the power formula, think: **"Power equals one over focal!"**

6. Visual Suggestion

6. Visual Suggestion

A ray diagram showing a converging lens with focal points marked, illustrating light paths converging at the focal point. This helps visualize focal length and power.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class 12 Physics, Chapter on Optics.

Question 4 of 5 NDA MCQ

Detailed Explanation

Correct Answer

โœ“ Option (A) is correct. The formula applies specifically to spherical mirrors.

๐Ÿ“– Governing Law / Core Concept

According to the New Cartesian Sign Convention, the formula for mirrors is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] where: - \( f \) = focal length (meters), - \( v \) = image distance (meters), - \( u \) = object distance (meters).

๐Ÿงช Step-by-Step Breakdown

For spherical mirrors: - **Sign Convention**: - Focal length (\( f \)) is taken positive for concave mirrors. - Object distance (\( u \)) is negative when the object is in front of the mirror. - Image distance (\( v \)) is positive if the image is formed on the same side as the object. Thus, the relationship holds for spherical mirrors only.

๐Ÿ” Option Analysis

- **Option B**: It applies only to spherical lenses. Incorrect because the formula is not valid for lenses. - **Option C**: It applies to spherical mirrors as well as spherical lenses. Incorrect because lenses have different conventions. - **Option D**: It is an invalid formula. Incorrect as it is valid for spherical mirrors.

โšก Mnemonic / Speed-Run

Remember: "M" for Mirrors, "L" for Lenses. Use "Molar" to recall that mirrors follow the Cartesian convention.

6. Visual Suggestion

6. Visual Suggestion

A ray diagram showing the path of light through a concave mirror, highlighting the focal point and the relationships between object distance, image distance, and focal length.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class 12 Physics, Chapter 10 (Light).

Question 5 of 5 NDA MCQ

The focal length of a concave lens is 0.5 m. The power of the lens is

Detailed Explanation

Correct Answer

โœ“ Option D is correct. The power of a concave lens is negative.

๐Ÿ“– Governing Law / Core Concept

The power \( P \) of a lens is defined as the reciprocal of its focal length \( f \) (in meters):

\[ P = \frac{1}{f} \]

๐Ÿงช Step-by-Step Breakdown

Given the focal length of the concave lens:

The value of \( f = -0.5 \, m \) (negative, as it is a concave lens).

Substituting into the power formula:

\[ P = \frac{1}{-0.5} \] \end{aligned} \]
\[ P = -2 \, D \]

๐Ÿ” Option Analysis

  • Option A: Incorrect; the power should be negative.
  • Option B: Incorrect; the magnitude is correct, but the sign is wrong.
  • Option C: Incorrect; positive power does not apply to concave lenses.

โšก Mnemonic / Speed-Run

Recall that for concave lenses, \( P = \frac{1}{f} \) where \( f \) is negative.

6. Visual Suggestion

6. Visual Suggestion

Illustrate the concept of a concave lens with ray diagrams showing how light diverges and the negative focal length effect.

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class XII Physics, Optics Chapter.

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