General Science

Eclipses

Chapter: Space & Astronomy

Question 1 of 5 NDA MCQ

Which of the following positions of Sun, Earth and Moon is/are suitable for Spring Tide ?

1. SYZYGY Conjunction

2. SYZYGY Opposition

3. Quadrature

 Select the correct answer using the code given below :

Detailed Explanation

Correct Answer

โœ“ Option C is correct. Spring tides occur during conjunction and opposition positions of the Sun, Earth, and Moon.

๐Ÿ“– Governing Law / Core Concept

Spring tides are the result of the alignment (syzygy) of the Sun, Earth, and Moon, where gravitational forces combine to create higher tides.

๐Ÿงช Step-by-Step Breakdown

1. Conjunction: When the Moon is between the Sun and Earth, during a new moon, gravitational forces from the Sun and Moon combine, resulting in higher high tides.

2. Opposition: During a full moon, when the Sun, Earth, and Moon are aligned, the same principle applies, leading to spring tides.

3. Quadrature: This occurs when the Sun and Moon are at 90ยฐ relative to the Earth, resulting in lower tides known as neap tides.

๐Ÿ” Option Analysis

  • 1. SYZYGY Conjunction: Correct, causes spring tide.
  • 2. SYZYGY Opposition: Correct, causes spring tide.
  • 3. Quadrature: Incorrect, leads to neap tide.

โšก Mnemonic / Speed-Run

Remember: Spring tides = Syzygy (Conjunction + Opposition). Use "Full & New" as triggers for memory.

6. Visual Suggestion

6. Visual Suggestion

Illustrate the positions of the Sun, Earth, and Moon during conjunction and opposition to show alignment causing spring tides versus quadrature causing neap tides.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class 9 Science, Chapter 8 (Motion and Force).

Question 2 of 5 NDA MCQ

Which of the following statements regardingneap tides is/are correct?

1. It occurs every 14-15 days, which coincideswith the first and third quarter of the Moon.

2. This tide has a small tidal range because the gravitational forces of the Moon and the Sun are in quadrature.

Select the answer using the code given below:

Detailed Explanation

Correct Answer

โœ“ Option C is correct. Both statements regarding neap tides are accurate.

๐Ÿ“– Governing Law / Core Concept

Neap tides are the result of the gravitational interaction between the Earth, Moon, and Sun. They occur during the first and third quarters of the Moon, leading to a smaller tidal range due to the alignment of the Moon and Sun.

๐Ÿงช Step-by-Step Breakdown

  • 1. Timing: Neap tides occur approximately every 14-15 days.
  • 2. Alignment: These tides occur at the first and third quarters of the Moon when the Sun and Moon form a right angle with respect to Earth.
  • 3. Tidal Range: The gravitational forces of the Moon and Sun counterbalance each other during this period, resulting in a smaller tidal range.

๐Ÿ” Option Analysis

  • Option A: Incorrect, as it claims only the first statement is correct.
  • Option B: Incorrect, as it claims only the second statement is correct.
  • Option D: Incorrect, as it states that neither statement is correct.

โšก Mnemonic / Speed-Run

Remember: "Neap - Quarter, Weak" to recall that neap tides occur in the first and third quarters of the Moon with a smaller tidal range.

6. Visual Suggestion

6. Visual Suggestion

A diagram showing the Earth, Moon, and Sun at the first and third quarters of the Moon, illustrating their respective positions and the resulting smaller tidal range.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class 11 Science, Chapter on The Earth and Environment.

Question 3 of 5 NDA MCQ

One parsec in astronomical units (A.U.) is about

Detailed Explanation

Correct Answer

โœ“ Option C is correct. One parsec equals approximately 2.06 × 105 A.U.

๐Ÿ“– Core Concept

Parsec is a unit of length used in astronomy to measure large distances to astronomical objects outside the Solar System. It is derived from the method of parallax in astronomical measurements.

๐Ÿงช Step-by-Step Breakdown

1 parsec (pc) can be defined as the distance at which one astronomical unit subtends an angle of one arcsecond. To convert parsecs to astronomical units:

\[ 1 \text{ parsec} \approx 3.26 \text{ light-years} \]

Since:

\[ 1 \text{ light-year} = 1 \text{ A.U.} \times \text{seconds in a year} / \text{speed of light} \]

By calculating this relationship, we conclude:

\[ 1 \text{ parsec} \approx 2.06 \times 10^{5} \text{ A.U.} \]

๐Ÿ” Option Analysis

  • Option A: Incorrect; 2 × 103 A.U. is too small.
  • Option B: Incorrect; 2 × 104 A.U. is also too small.
  • Option D: Incorrect; 2 × 106 A.U. is excessive.

โšก Mnemonic / Speed-Run

Remember: 1 parsec ≈ 2.06 × 105 A.U. for quick recall.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against standard astronomical references and NCERT Class XII Physics, Chapter on Waves.

Question 4 of 5 NDA MCQ

Which one of the following is the lowest possible temperature?

Detailed Explanation

Correct Answer

โœ“ Option D is correct. This is the lowest possible temperature based on the absolute temperature scale.

๐Ÿ“– Governing Law / Core Concept

The lowest possible temperature is defined by absolute zero, represented as: \[ T_{\text{absolute}} = 0\, \text{K} = -273.15\, \text{ยฐC} \]

๐Ÿงช Step-by-Step Breakdown

Temperature scales: - Celsius is based on the freezing (0 ยฐC) and boiling points (100 ยฐC) of water. - Kelvin is an absolute scale starting at absolute zero (0 K = -273.15 ยฐC). The relationship indicates no lower limit exists below absolute zero, making: \[ -273\, \text{ยฐC} \text{ the lowest possible temperature.} \]

๐Ÿ” Option Analysis

- **Option A: 0ยฐC** - Freezing point of water. - **Option B: -73ยฐC** - Cold, but above absolute zero. - **Option C: -173ยฐC** - Cold, but still higher than absolute zero.

โšก Mnemonic / Speed-Run

Remember: **Absolute Zero (-273 ยฐC)** = no thermal energy, basis for Kelvin scale.

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class XI Physics, Chapter 1 (Physical World) and temperature scales.

Question 5 of 5 NDA MCQ

Light year is a unit of measurement of

Detailed Explanation

Correct Answer

โœ“ Option (a) is correct. A light year is a measurement of distance, specifically the distance light travels in one year.

๐Ÿ“– Governing Law / Core Concept

A light year is defined as the distance that light travels in a vacuum in one Julian year, which is approximately 9.461 trillion kilometers (about 5.879 trillion miles).

๐Ÿงช Step-by-Step Breakdown

Definition:

\[ \text{Distance} = \text{Speed of Light} \times \text{Time} \]
By calculating for one year:
\[ \text{Distance} = 299,792,458 \, \text{m/s} \times 31,536,000 \, \text{s} \]
Where: - Speed of Light \(c = 299,792,458 \, \text{m/s}\) - \(1 \text{ year} = 31,536,000 \text{ seconds}\) Resulting in:
\[ \approx 9.461 \times 10^{12} \, \text{km} \]

๐Ÿ” Option Analysis

  • Option (b): A time interval in years - Incorrect; it refers to duration, not distance.
  • Option (c): Amount of light received on Earth in a year - Incorrect; this concept relates to luminosity, not distance.
  • Option (d): Mass of atoms - Incorrect; measurably unrelated to light or distance units.

โšก Mnemonic / Speed-Run

To remember what a light year measures, think: "Light travels like a swift year - very far distances."

๐Ÿ“– Factual Verification & Reference

๐Ÿ“– Factual Verification & Reference:

Verified against NCERT Class 12 Physics, Chapter on Waves and Optics.

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