Elementary ideas of work, power, and energy Questions
Chapter: Mechanics | Total Available: 19 Real Questions
A mass M is dragged by a pulley on a horizontalplane by a force anti–parallel to its displacement.The work done in pulling the mass M is
Correct Answer
๐ Governing Law / Core Concept
The work done \( W \) by a force is given by the formula:๐งช Step-by-Step Breakdown
The force is applied anti-parallel to the displacement, therefore: \( \theta = 180^\circ \) Calculating the work done:๐ Option Analysis
- Option (a): Zero - Incorrect, as work is negative. - Option (b): Positive - Incorrect, as work is negative. - Option (c): Infinite - Incorrect, as work does not approach infinity in this scenario. - Option (d): Negative - Correct, as derived above.โก Mnemonic / Speed-Run
Remember: "Work and force dance; when they clash, work is negative." Forces opposing displacement yield negative work.6. Visual Suggestion
6. Visual Suggestion
A force diagram showing a horizontal surface with a mass \( M \) attached to one end of a pulley. Illustrate the force vector pointing opposite to the direction of displacement, indicating the negative work done.
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter 6 (Work, Energy and Power).
If the work done on the system or by the system is zero, which one of the following statements for a gas kept at a certain temperature is correct?
Correct Answer
๐ Governing Law / Core Concept
The first law of thermodynamics states that:
Where: \(\Delta U\) = change in internal energy, Q = heat transferred, W = work done.
๐งช Step-by-Step Breakdown
Given that the work done (W = 0), the equation simplifies to:
This indicates that the change in internal energy is directly equal to the heat transferred in or out of the system.
๐ Option Analysis
- Option (b): Change in internal energy of the system is less than heat transferred. Incorrect; they are equal.
- Option (c): Change in internal energy of the system is more than the heat flow. Incorrect; they are equal.
- Option (d): Cannot be determined. Incorrect; it is determinable.
โก Mnemonic / Speed-Run
Remember: Energy transfer equals heat flow when no work is done.
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter 6 (Thermodynamics).
A solid disc and a solid sphere have the same mass and same radius. Which one has the higher moment of inertia about its centre of mass?
Correct Answer
๐ Governing Law / Core Concept
The moment of inertia (\(I\)) about the center of mass for a solid disc and a solid sphere is defined as:
๐งช Step-by-Step Breakdown
Given that both the disc and sphere have the same mass (\(m\)) and radius (\(r\)), we can directly substitute the values into their respective moment of inertia formulas.
Now comparing the two:
This shows that the moment of inertia of the disc is greater than that of the sphere.
- Moment of Inertia of a disc: \(I = \frac{1}{2} m r^2\)
- Moment of Inertia of a sphere: \(I = \frac{2}{5} m r^2\)
A comparative bar graph showing the moment of inertia values for both a disc and a sphere of the same mass and radius, clearly illustrating that the disc's moment of inertia is higher.
Verified against standard mechanics textbooks, including "Fundamentals of Physics" by Halliday, Resnick, and Walker.
When a ball bounces off the ground, which of the following changes suddenly?
Correct Answer
๐ Governing Law / Core Concept
The momentum \( p \) of an object is defined as the product of its mass \( m \) and its velocity \( v \):
๐งช Step-by-Step Breakdown
Upon bouncing, the direction of the velocity of the ball changes rapidly, resulting in:
Where \( v' \) is the velocity after the bounce (upward) and \( v \) is the velocity before (downward). This rapid change implies:
๐ Option Analysis
- A: Its speed - While speed may change, it doesn't change suddenly due to the velocity change being instantaneous.
- C: Its kinetic energy - Kinetic energy also changes but not necessarily suddenly across all bounces.
- D: Its potential energy - This alters gradually during the ascent and descent of the ball.
โก Mnemonic / Speed-Run
Remember: Momentum is impacted by the velocity change; hence, think "Momentum suddenly changes when direction does!"
6. Visual Suggestion
6. Visual Suggestion
Illustration showing a ball's trajectory with marked speed and momentum vectors before and after the bounce to depict sudden change in momentum.
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter on Momentum and Impulse.
A thin disc and a thin ring, both have mass M and radius R. Both rotate about axes through their center of mass and perpendicular to their surfaces at the same angular velocity. Which of the following is true?
Correct Answer
๐ Governing Law / Core Concept
The rotational kinetic energy of a body is given by the formula:
Where \( K.E. \) is kinetic energy, \( I \) is the moment of inertia, and \( \omega \) is the angular velocity.
๐งช Step-by-Step Breakdown
For a thin ring:
Thus, the kinetic energy becomes:
For a thin disc:
So, the kinetic energy for the disc is:
Comparing the two kinetic energies:
- K.E. of Ring: \( \frac{1}{2} M R^2 \omega^2 \)
- K.E. of Disc: \( \frac{1}{4} M R^2 \omega^2 \)
Since \( \frac{1}{2} > \frac{1}{4} \), the ring has higher kinetic energy than the disc.
๐ Option Analysis
- Option (b): The disc has higher kinetic energy. Incorrect
- Option (c): The ring and the disc have the same kinetic energy. Incorrect
- Option (d): Kinetic energies of both bodies are zero since they are not in linear motion. Incorrect
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter 7 (System of Particles and Rotational Motion).
A negative work is done when an applied force F and the corresponding displacement S are
Correct Answer
๐ Governing Law / Core Concept
The work done \(W\) by a force is defined as:๐งช Step-by-Step Breakdown
For negative work, the angle \(\theta\) must be in the range where \( \cos(\theta) < 0\). This occurs when: \[ \theta = 180^\circ \] Thus, the work done can be represented as:๐ Option Analysis
- A: When perpendicular, \(W = 0\) since \(\cos(90^\circ) = 0\). No work. - B: When parallel, \(W = F \cdot S\), yielding positive work. - C: Correct; results in negative work as discussed. - D: Equal magnitudes alone do not determine work's sign.โก Mnemonic / Speed-Run
Remember: "Anti-parallel means opposing, causing negative work in motion."6. Visual Suggestion
6. Visual Suggestion
Illustrate a force vector \( F \) pointing to the left and a displacement vector \( S \) pointing to the right, forming a straight horizontal line. Label the angle \(\theta = 180^\circ\) for clarity.
๐ Factual Verification & Reference
Verified against NCERT Class XII Physics, Chapter on Work, Energy and Power.
The unit of the ratio between thrust and impulse is same as that of
Correct Answer
๐ Governing Law / Core Concept
The concepts involved here relate to thrust (\( T \)) and impulse (\( I \)), which are defined as follows: - Thrust, \( T = F \cdot \Delta t \) - Impulse, \( I = F \cdot \Delta t \) Where: - \( F \) = Force (measured in Newtons, \( N \)) - \( \Delta t \) = Time duration (measured in seconds, \( s \)) Thus, the ratio \( \frac{T}{I} \) can be expressed and analyzed.๐งช Step-by-Step Breakdown
1. Since \( T \) and \( I \) are both derived from the same principles of force over time: \[ \frac{T}{I} = \frac{F \cdot \Delta t}{F \cdot \Delta t} = 1 \] Therefore, the ratio \( \frac{T}{I} \) is dimensionless. 2. The frequency (\( f \)) is defined as cycles per second: \[ f = \frac{1}{T} \] 3. Resultantly, we see that the dimensional formula for thrust and impulse leads us to understand that both can be analyzed in terms of time-based ratios, primarily relating to cyclical motion or frequency.๐ Option Analysis
- Option (b) Speed: Dimensions are \( [L][T^{-1}] \) - Option (c) Wavelength: Dimensions are \( [L] \) - Option (d) Acceleration: Dimensions are \( [L][T^{-2}] \) The only concept sharing dimensional properties with our derived ratio is frequency.โก Mnemonic / Speed-Run
- Remember: Frequency is the "cycle count per second,โ directly linking it to thrust and impulse's time-related mechanics.6. Visual Suggestion
6. Visual Suggestion
A schematic diagram illustrating the relationship between thrust and impulse, with forces acting over time intervals, enabling the visualization of how these physical quantities relate to cycles per second.
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter 5 (Laws of Motion).
An object of mass 2000 g possesses 100 J kinetic energy. The object must be moving with a speed of
Solution
Option (a) is correct.
Explanation:
- Kinetic Energy Formula: \( KE = \frac{1}{2} m v^2 \)
- Mass Conversion: \( 1 \, g = 0.001 \, kg \)
A schematic can depict a moving object with labeled vectors showing velocity and kinetic energy, illustrating the relationship between mass and speed that results in the given kinetic energy.
Verified against NCERT Class XI Physics, Chapter 7 (System of Particles and Rotational Motion)
Work is said to be one Joule when a force of
Correct Answer
๐ Governing Law / Core Concept
Work (\( W \)) done by a constant force (\( F \)) is given by the formula:๐งช Step-by-Step Breakdown
To find the work done: - Given: \( F = 4 \, \text{N} \), \( d = 25 \, \text{cm} = 0.25 \, \text{m} \) Work calculation:๐ Option Analysis
- **Option (b)**: \( 2 \, \text{N} \cdot 1 \, \text{m} = 2 \, \text{J} \) (not correct). - **Option (c)**: \( 1 \, \text{N} \cdot 0.01 \, \text{m} = 0.01 \, \text{J} \) (not correct). - **Option (d)**: \( 1 \, \text{N} \cdot 0.5 \, \text{m} = 0.5 \, \text{J} \) (not correct).โก Mnemonic / Speed-Run
Remember: \( 1 \, \text{J} = 1 \, \text{N} \cdot 1 \, \text{m} \). Keep units consistent when calculating work; convert to meters when necessary.6. Visual Suggestion
6. Visual Suggestion
A diagram showing a horizontal surface with an object being pushed by a force. Include vectors for force and displacement and label the angle \( \theta \) as \( 0^\circ \).
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter 6 (Work, Energy, and Power).
The energy is always conserved for a system which is
Correct Answer
๐ Governing Law / Core Concept
According to the Law of Conservation of Energy, energy cannot be created or destroyed in an isolated system.
๐งช Step-by-Step Breakdown
In an isolated system, no matter or energy enters or leaves the system. Therefore, the total energy remains constant.
For a non-isolated system, external forces can do work, resulting in energy being transformed or transferred:
- Isolated System: \( E_{total} = E_{initial} \)
- Non-Isolated System: \( E_{total} = E_{initial} + W_{ext} \) (where \( W_{ext} \) is work done by external forces)
๐ Option Analysis
- B: Non-isolated systems experience energy transfer.
- C: Both cannot guarantee energy conservation.
- D: None of the above contradicts conservation laws.
โก Mnemonic / Speed-Run
Remember: "Isolated = Conserved, Non-isolated = Transferred."
6. Visual Suggestion
6. Visual Suggestion
A diagram illustrating isolated vs non-isolated systems, depicting energy flow in each type with arrows indicating energy transfer in non-isolated systems and none in isolated systems. Include labels to clarify.
๐ Factual Verification & Reference
Verified against NCERT Class XI Physics, Chapter: Work, Energy and Power.
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