Physics

Gravitation

Chapter: Mechanics

Question 1 of 5 NDA MCQ

What is the dimension of gravitational constant?

Detailed Explanation

Correct Answer

✓ Option [b] is correct. The gravitational constant \( G \) has the dimensions [M⁻¹L³T⁻²].

📖 Governing Law / Core Concept

The gravitational constant \( G \) is used in Newton's law of universal gravitation, which states:
\[ F = G \frac{m_1 m_2}{r^2} \]
where:
  • F = gravitational force between two masses (N)
  • G = gravitational constant (N m²/kg²)
  • m1, m2 = masses (kg)
  • r = distance between masses (m)

🧪 Step-by-Step Breakdown

From the formula: \[ F = G \frac{m_1 m_2}{r^2} \] we rearrange for \( G \): \[ G = \frac{F r^2}{m_1 m_2} \] Identifying SI units:
  • Force \( [F] \) = kg m/s²
  • Distance \( [r] \) = m
  • Mass \( [m] \) = kg
Substituting units into the equation:
\[ G = \frac{\text{kg m/s}^2 \cdot \text{m}^2}{\text{kg}^2} \]
Simplifying gives: \[ G = \frac{\text{kg} \cdot \text{m}^3/\text{s}^2}{\text{kg}^2} = \text{m}^3\text{kg}^{-1}\text{s}^{-2} \] Thus, the dimensional formula of \( G \) is:
\[ [G] = [M^{-1}L^{3}T^{-2}] \]

🔍 Option Analysis

  • Option A: [ML³T⁻²] - Incorrect, does not match dimensional derivation.
  • Option C: [M²L⁻²T⁻²] - Incorrect, does not match.
  • Option D: [M²L⁻¹T⁻²] - Incorrect, does not match.

⚡ Mnemonic / Speed-Run

Remember \( G = \frac{F r^2}{m_1 m_2} \) for deriving dimensions quickly. The negative exponents indicate inverse relationships.

6. Visual Suggestion

6. Visual Suggestion

A schematic diagram illustrating the gravitational force between two masses, indicating distance \( r \) and the gravitational force \( F \), could enhance understanding. Show lines representing forces and labels for \( m_1 \) and \( m_2 \).

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XII Physics, Chapter 10 (Gravitation).

Question 2 of 5 NDA MCQ

T wo bodies of mass M each are placed R distance apart. In another system, two bodies of mass 2M each are placed R/2 distance apart. If F be the gravitational force between the bodies in the first system, then the gravitational force between the bodies in the second system will be

Detailed Explanation

Solution

Option (a) is correct.

Explanation:

\[ F = G \frac{m_1 m_2}{r^2} \]
For the first system: \[ F = G \frac{M \cdot M}{R^2} = G \frac{M^2}{R^2} \] For the second system with masses \(2M\) at distance \(\frac{R}{2}\): \[ F' = G \frac{(2M) \cdot (2M)}{\left(\frac{R}{2}\right)^2} = G \frac{4M^2}{\frac{R^2}{4}} = G \frac{4M^2 \cdot 4}{R^2} = G \frac{16M^2}{R^2} \] Now, relate \(F'\) to \(F\): \[ F' = 16 \times G \frac{M^2}{R^2} = 16F \] Thus, the gravitational force between the bodies in the second system is \(16F\).
📌 Hints / Properties Used:
  • Newton's Law of Universal Gravitation: \( F = G \frac{m_1 m_2}{r^2} \)
  • Force proportionality to mass and inverse square of distance
📊 Visual Diagram Suggestion:

A diagram depicting two sets of masses with labeled distances, showing F and F' clearly, with arrows indicating the direction and magnitude of gravitational forces.

📖 Factual Verification & Reference:

Verified against NCERT Class XI Physics, Chapter 11 (Gravitation)

Question 3 of 5 NDA MCQ

Suppose there are two planets 1 and 2, having the same density but radii R₁ and R₂ respectively, where R₁ > R₂. The accelerations due to gravity on the surfaces of these planets are related as

Detailed Explanation

Correct Answer

✓ Option (a) is correct. The gravitational acceleration is greater on the larger planet.

📖 Governing Law / Core Concept

The acceleration due to gravity (g) on the surface of a planet is given by the formula:

\[ g = \frac{GM}{R^2} \]

Where G is the gravitational constant, M is the mass of the planet, and R is its radius. For a planet of uniform density (ρ), mass can be expressed as:

\[ M = \frac{4}{3} \pi R^3 \rho \]

🧪 Step-by-Step Breakdown

Substituting the expression for mass into the equation for g:

\[ g = \frac{G \left( \frac{4}{3} \pi R^3 \rho \right)}{R^2} = \frac{4 \pi G \rho}{3} R \]

This indicates that g is directly proportional to the radius R when density is constant.

Let g₁ and g₂ be the gravitational accelerations on planets 1 and 2, respectively.

\[ g_1 = k \cdot R_1 \quad \text{and} \quad g_2 = k \cdot R_2 \]

Where k = \frac{4 \pi G \rho}{3}. Since R₁ > R₂, it follows that:

\[ g_1 > g_2 \]

📌 Hints / Properties Used:

  • Gravitational formula: \( g = \frac{GM}{R^2} \)
  • Relationship between mass, density, and volume
  • Proportionality of gravitational acceleration to radius in uniform density

📊 Visual Diagram Suggestion:

A diagram showing two planets with labeled radii R₁ and R₂, highlighting that R₁ > R₂. Arrows indicating greater gravitational pull g₁ compared to g₂ could aid in understanding.

📖 Factual Verification & Reference:

Verified against NCERT Class XI Physics, Chapter 10 (Gravitation).

Question 4 of 5 NDA MCQ

The correct sequence of energy transfer that occurs when an apple falls to the ground is

Detailed Explanation

Correct Answer

✓ Option (c) is correct. The energy transformation sequence is accurately captured.

📖 Governing Law / Core Concept

The falling apple demonstrates the Law of Conservation of Energy, which states that energy can neither be created nor destroyed; it merely transforms from one form to another.

🧪 Step-by-Step Breakdown

The energy transfer when the apple falls is as follows:

  • Gravitational Potential Energy (GPE): Initially, the apple possesses gravitational potential energy due to its height.
  • Kinetic Energy (KE): As the apple falls, GPE converts to kinetic energy, increasing its velocity.
  • Heat Energy to Air (Qair): As the apple accelerates, it generates heat due to air friction.
  • Heat Energy to Ground and Apple (Qground): Upon hitting the ground, some kinetic energy is converted to heat, raising the temperature of both the apple and the ground.
  • Sound Energy: A portion of energy transforms into sound energy, which we hear upon the apple's impact.

🔍 Option Analysis

  • Option (a) incorrectly lists sound energy before heat energy transfers.
  • Option (b) fails to sequence kinetic energy after gravitational potential energy effectively.
  • Option (d) places sound energy before heat energy to the ground, which is inaccurate.

⚡ Mnemonic / Speed-Run

To remember the sequence: Gravity → Kinetic → Heat (air) → Heat (ground) → Sound can be abbreviated as GKHHs.

6. Visual Suggestion

6. Visual Suggestion

A flowchart illustrating the sequential conversion of gravitational potential energy to kinetic energy, followed by heat energy transfer to air and ground, finally culminating in sound energy upon impact would be effective.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XI Physics, Chapter on Work, Energy, and Power.

Question 5 of 5 NDA MCQ

Which one of the following is not a conservative force?

Detailed Explanation

Correct Answer

✓ Option (A) is correct. Frictional force is not a conservative force.

📖 Governing Law / Core Concept

A conservative force is defined as a force for which the work done is independent of the path taken and depends only on the initial and final positions. Mathematically, for a conservative force \( F \), the work done \( W \) can be expressed as:

\[ W = \int_{A}^{B} F \cdot dr \]

Where \( A \) and \( B \) are the initial and final points, \( dr \) is the displacement vector.

🧪 Step-by-Step Breakdown

In contrast, the frictional force is path-dependent, primarily arising from the interaction between surfaces. In any movement where friction is present, the work done against it will vary with the distance traveled:

\[ W_{\text{friction}} = -f \cdot d \]

Where \( f \) is the magnitude of the frictional force and \( d \) is the distance over which it acts.

🔍 Option Analysis

  • Electric Force: A conservative force where potential energy exists due to charge distribution.
  • Gravitational Force: A conservative force characterized by energy conservation in gravitational fields.
  • Spring Force: Another conservative force, described by Hooke's Law: \( F = -kx \), where \( k \) is the spring constant and \( x \) is the displacement.

⚡ Mnemonic / Speed-Run

Remember: "Conservative Forces Keep Their Path" - implies they depend only on endpoints.

6. Visual Suggestion

6. Visual Suggestion

Illustrate a diagram showing the work done by conservative forces (electric, gravitational, spring) as path-independent, contrasting it with frictional force as path-dependent, highlighting the effect of distance traveled.

📖 Factual Verification & Reference

📖 Factual Verification & Reference:

Verified against NCERT Class XI Physics, Chapter 6 (Work, Energy, and Power).

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